<?php //function function nextWeeksDay($date_begin,$nbrweek) { $nextweek=array(); for($i = 1; $i <= $nbrweek; $i++) { // 52 week in one year of coursewww.phpfensi.com $nextweek[$i]=date('D d M Y', strtotime('+'.$i.' week',$date_begin)); } return $nextweek; } /// end function /// example of a select date // var $date_begin = strtotime('06-05-2010'); //D Day Month Year - like function format. $nbrweek=52; // call function $result=nextWeeksDay($date_begin,$nbrweek); // Preview for($i = 1; $i <= $nbrweek; $i++) { echo '<br> - '.$result[$i]; } ?> <?php $str = 'Not Good'; // previous to PHP 5.1.0 you would compare with -1, instead of false if (($timestamp = strtotime($str)) === false) { echo "The string ($str) is bogus"; } else { echo "$str == " . date('l dS o F Y h:i:s A', $timestamp); } ?> <?php echo strtotime("now"), " "; echo strtotime("10 September 2000"), " "; echo strtotime("+1 day"), " "; echo strtotime("+1 week"), " "; echo strtotime("+1 week 2 days 4 hours 2 seconds"), " "; echo strtotime("next Thursday"), " "; echo strtotime("last Monday"), " "; ?>
function get_working_days($to_date) { $holidays = array( 1 => array(10), //2011 ... 2 => array(11), 3 => array(21), //... 2011 4 => array(29,30), //2010 ... 5 => array(3,4,5), 6 => array(), 7 => array(19), 8 => array(11,12,13), 9 => array(20,23), 10 => array(11), 11 => array(3,23), 12 => array(23) //... 2010 ); for($to_date, $w = 0, $i = 0, $x = time(); $x < $to_date; $i++, $x = strtotime("+$i day")) { if(date("N",$x) < 6 &! in_array(date("j",$x),$holidays[date("n",$x)])) $w++; } return $w; } //Usage: echo get_working_days(strtotime("2011-01-08"));
希望本文所述对大家的PHP程序设计有所帮助。